I.3.19a
5/24/2021
It follows from the multivariable chain rule that if F has a
polynomial inverse function G : kN → kN, then JF has a polynomial
reciprocal, so is a nonzero constant. The Jacobian conjecture is the following
partial converse:
Well folks, what can I say. I'm a little stumped, and I've about had it for now
with this section. This section has 21 exercises in total, making it the longest
section in this chapter (The next section for instance has less than half as many).
I've done all all of them but 3.14, 3.15bd, 3.17, 3.18, 3.20, 3.21. These 5.5
exercises can be done another day. It's not like I haven't gone back to previous
sections in the past. If I have to struggle with integrally closed domains in the
future, we'll cross that bridge when we get to it. So this is le season finale.
Sometimes, lazy evaluation is useful... Sometimes. In my past of flaily self-learning
math attempts, I had an interesting revelation: Hey, instead of going through
everything chronologically, why don't I start from the chapter I want to be in and
figure things out from there. So I started from here, and proceeded to fill in
knowledge as needed. I learned absolutely nothing and wasted a week. So it goes.
On the other hand, the reason I know enough topology and algebra to barely
scrape through these exercises isn't via a thorough reading of them. It was a very
irresponsible, section-skippy, exercise-exclusionary, lazy reading, sometimes with
nightcore playing the background (THIS IS MY MELODY AND IT'S JUST A
RAVERS FANTASY ♪ CAUSE I KNOW IF YOU'RE IN LOVE
WITH ME TONIIIIIIIIGHT ♪ WE'RE RAVING THROUGH THE
NIIIIIIGHT ♪ WHAT THE FUCKING FUCK ♪ IS A
"SEPARABLE EXTENSION" ♪ SOMEONE FUCKING HELP ME
FUCKING MOTHERFUCKING MOTHERFUCKER ♪)
Breathe in. *Inhales* Find your balance........ Yes...... Breathe out. *Exhales*
Think of the ocean..... all from the little wavelets *Inhale* to all the big wide
waves *Exhale*..... Both are important..... Both serve their own purpose in this
world...... Find your middle ground.... Do you see it? Yes....... Touch it..... Feel
it...... Stay calm.... *Inhale* Don't panic... *Exhale*.... Now... Let's check the
performance meter:
The point of this blog was to build a habit of doing math. 3 sections in, I'd like to
reveal to you, reader, that I have not built a "habit" at all. There is still no set
time for when I do math. I do it at sporadic, random times, on whim rather than
discipline. I generally put it off as long as I can before thinking "God
fucking damn it, the blog needs to be updated" and I then stumble my way
through an exercise. The accountability is working, in that the job gets done
(slowly). But what I've learned over the X months since starting this
blog is that "discipline" is completely lost on me. It has been X months
and I have not developed a shred of discipline. My brain is officially too
broken for consistency. I can go on brainpickings.org and go "ooooo" at the
schedules of Benjamin Franklin or Mozart or whatever the fuck, but I now
know that that's all useless information for me. I can no longer adapt
my brain to my circumstances, I have to adapt my circumstances to my
brain. One is usually morally obliged to avoid the latter, because that
involves shaking things up around oneself rather than just within oneself,
but I'm amoral so its okay. Basically, I'd like to stop being a pussy and
pull the trigger on moving locations/jobs. "Nice blog, holeinmyheart,
where can I subscribe"... Subscribe to this *unzips* (<— not funny).
BTW: this exercise is easy. I mean it's weird that we suddenly brought in calculus
here, but it's fine. I decided to look up the Jacobian matrix Wikipedia page for a
bit of refresher, and I noticed that the unsolved problem of part (b) was linked
there, as its own page: Jacobian Conjecture. Very interesting. So I scrolled down
and saw this:
........which is basically the solution to this exercise.
Let me elaborate. Let's look at the Jacobian matrix formulation of the
multivariable chain rule
Let I denote the identity matrix and id be the identity morphism. Then
I | = Jid | ||
= Jϕ-1∘ϕ | |||
= (Jϕ-1 ∘ ϕ) ⋅ Jϕ | |||
1 | = det(Jϕ-1 ∘ ϕ) ⋅ det(Jϕ) |